soluzione
Scomporre
x
3
+ 7x
2
y + 14xy
2
+ 8y
3
=
1
+7
+14
+8
-1
-1
-6
-8
1
+6
+8
//
(x-1); P(1)= + 1 + 7 + 14 + 8 ≠ 0
(x+1); P(1)= - 1 + 7 - 14 + 8 = 0
= (x + y)· (x
2
+ 6xy + 8y
2
) =
= (x + y) (x + 2y) (x + 4y)