soluzione
Calcolare
(
1
8x
3
+ 1
-
1
2x + 1
)
·
64x
6
- 1
2x
2
- x
-
(
1
8x
3
- 1
-
1
2x - 1
)
·
64x
6
- 1
2x
2
- x
=
=
(
1
(2x + 1)(4x
2
- 2x +1)
-
1
2x + 1
)
·
64x
6
- 1
2x
2
- x
-
(
1
(2x - 1)(4x
2
+ 2x +1)
-
1
2x - 1
)
·
64x
6
- 1
2x
2
- x
=
=
1 - (4x
2
- 2x + 1)
(2x + 1)(4x
2
- 2x +1)
·
64x
6
- 1
2x
2
- x
-
1 - (4x
2
+ 2x + 1)
(2x - 1)(4x
2
+ 2x +1)
·
64x
6
- 1
2x
2
- x
=
=
1 - 4x
2
+ 2x - 1
(2x + 1)(4x
2
- 2x +1)
·
64x
6
- 1
2x
2
- x
-
1 - 4x
2
- 2x - 1
(2x - 1)(4x
2
+ 2x +1)
·
64x
6
- 1
2x
2
- x
=
=
- 4x
2
+ 2x
(2x + 1)(4x
2
- 2x +1)
·
64x
6
- 1
2x
2
- x
-
- 4x
2
- 2x
(2x - 1)(4x
2
+ 2x +1)
·
64x
6
- 1
2x
2
- x
=
=
-2x(2x - 1)
(2x + 1)(4x
2
- 2x + 1)
·
(2x - 1)(2x + 1)(4x
2
+ 2x + 1)(4x
2
- 2x + 1)
x(2x - 1)
+
(vado a capo col meno:
qui metto piu' ed a capo metto meno
-
-2x(2x + 1)
(2x-1)(4x
2
+2x+1)
·
(2x - 1)(2x + 1)(4x
2
+ 2x + 1)(4x
2
- 2x + 1)
x(2x - 1)
=
=
- 2(2x - 1)(4x
2
+ 2x + 1)
-
[
-2(2x + 1)
2
(4x
2
- 2x + 1)
2x - 1
]
=
=
- 2(2x - 1)
2
(4x
2
+ 2x + 1) +2(2x + 1)
2
(4x
2
- 2x + 1)
2x - 1
=
=
- 2(2x - 1) (8x
3
- 1) +2(2x + 1)(8x
3
+ 1)
2x - 1
=
=
- 32x
4
+ 4x + 16 x
3
- 2 + 32x
4
+ 4x + 16 x
3
+ 2
2x - 1
=
=
32x
3
+ 8x
2x - 1
=
=
8x(4x
2
+ 1)
2x - 1
=